n^2-25n+144=0

Solution for n^2-25n+144=0 equation:

n^2-25n+144=0

a = 1; b = -25; c = +144;
Δ = b2-4ac
Δ = -252-4·1·144
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-7}{2*1}=\frac{18}{2}
=9
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+7}{2*1}=\frac{32}{2}
=16
$